新语法糖简化数组创建
智能大石头 authored at 2023-11-22 20:23:53
3.46 KiB
X
using System;
using System.Collections.Generic;
using System.Text;

namespace NewLife.Data;

/// <summary>经纬坐标的一维编码表示</summary>
/// <remarks>
/// 文档 https://newlifex.com/core/geo_hash
/// 
/// 一维编码表示一个矩形区域,前缀表示更大区域,例如北京wx4fbzdvs80包含在wx4fbzdvs里面。
/// 这个特性可以用于附近地点搜索。
/// GeoHash编码位数及距离关系:
/// 1位,+-2500km;
/// 2位,+-630km;
/// 3位,+-78km;
/// 4位,+-20km;
/// 5位,+-2.4km;
/// 6位,+-610m;
/// 7位,+-76m;
/// 8位,+-19m;
/// 9位,+-2m;
/// </remarks>
public static class GeoHash
{
    #region 属性
    private static readonly Int32[] BITS = [16, 8, 4, 2, 1];
    private const String _base32 = "0123456789bcdefghjkmnpqrstuvwxyz";
    private static readonly Dictionary<Char, Int32> _decode = new();
    #endregion

    #region 构造
    static GeoHash()
    {
        for (var i = 0; i < _base32.Length; i++)
        {
            _decode[_base32[i]] = i;
        }
    }
    #endregion

    #region 方法
    /// <summary>编码坐标点为GeoHash字符串</summary>
    /// <param name="longitude">经度</param>
    /// <param name="latitude">纬度</param>
    /// <param name="charCount">字符个数。默认9位字符编码,精度2米</param>
    /// <returns></returns>
    public static String Encode(Double longitude, Double latitude, Int32 charCount = 9)
    {
        Double[] longitudeRange = [-180, 180];
        Double[] latitudeRange = [-90, 90];

        var isEvenBit = true;
        UInt64 bits = 0;
        var len = charCount * 5;
        for (var i = 0; i < len; i++)
        {
            bits <<= 1;

            // 轮流占用信息位
            var value = isEvenBit ? longitude : latitude;
            var rang = isEvenBit ? longitudeRange : latitudeRange;

            var mid = (rang[0] + rang[1]) / 2;
            if (value >= mid)
            {
                bits |= 0x1;
                rang[0] = mid;
            }
            else
            {
                rang[1] = mid;
            }

            isEvenBit = !isEvenBit;
        }

        bits <<= (64 - len);

        // base32编码
        var sb = new StringBuilder();
        for (var i = 0; i < charCount; i++)
        {
            var pointer = (Int32)((bits & 0xf800000000000000L) >> 59);
            sb.Append(_base32[pointer]);
            bits <<= 5;
        }
        return sb.ToString();
    }

    /// <summary>解码GeoHash字符串为坐标点</summary>
    /// <param name="geohash"></param>
    /// <returns></returns>
    public static (Double Longitude, Double Latitude) Decode(String geohash)
    {
        Double[] latitudeRange = [-90, 90];
        Double[] longitudeRange = [-180, 180];

        var isEvenBit = true;
        for (var i = 0; i < geohash.Length; i++)
        {
            var ch = _decode[geohash[i]];
            for (var j = 0; j < 5; j++)
            {
                // 轮流解码信息位
                var rang = isEvenBit ? longitudeRange : latitudeRange;
                var mid = (rang[0] + rang[1]) / 2;
                if ((ch & BITS[j]) != 0)
                    rang[0] = mid;
                else
                    rang[1] = mid;

                isEvenBit = !isEvenBit;
            }
        }

        var longitude = (longitudeRange[0] + longitudeRange[1]) / 2;
        var latitude = (latitudeRange[0] + latitudeRange[1]) / 2;

        return (longitude, latitude);
    }
    #endregion
}